mgo+co2=mgco3 what is the coefficents thanks

Question

trying to balance unbalanced chemical reaction

Answer 1

We want the number of each element on the Reactants (Left side) to be equal to the number of each element on the Product side (Right side). So lets begin with the Reactants

When you count the number of each element of the reactants you get:

Mg_reactant = 1 (from MgO)

C_reactant = 1 (from CO₂)

O_reactant =3 (1 from MgO and 2 from CO₂)

Then you count the number of each element of the product you get:

Mg_product = 1 (from MgCO₃)

C_product = 1 (from MgCO₃)

O_product = 3 (from MgCO₃)

Then compare the totals for each element

Mg_reactant = 1 ; Mg_product = 1 :conclusion ---> no change

C_reactant = 1 ; C_product = 1 :conclusion ---> no change

O_reactant = 3 ; O_product = 3 :conclusion ---> no change

Since there was no imbalance your question becomes your answer.

If there was an imbalance found, you would adjust the Coefficient (the number in front of each compound or element) until the count for the element on both the reactant and product side are equal.

For example; the equation Mg + N₂ ---> Mg₃N₂ when we start to balance the Mg we get the following:

Mg_reactant = 1 (from elemental Mg) and Mg_product = 3 (from Mg₃N₂)

1 : 3 ---> since they don't equal each other you must increase the coefficient of the reactant to 3

3Mg + N₂ ---> Mg₃N₂

↑ Since 3Mg is equivalent to Mg₃ and the N₂ are balanced already the final equation is this equation

 

 
 

 

Answer 2

Question: mgo+co2=mgco3 what is the coefficents thanks
trying to balance unbalanced chemical reaction

 

Answer:

 

MgO + CO₂ → MgCO₃ is already balanced.  

 

You can check each element individually.  

Mg: one on each side of the arrow.

O: three on each side.

C: one on each side.

 

Done.

 

Each coefficient in this equation is 1.  

 

Note: Coefficients of 1 are not written.  When coefficients are absent, 1 is assumed.

Answer 3

4 MgO + 4 CO₂ = 4 MgCO₃