In photosynthesis, carbon dioxide and water combine in the presence of sunlight tho produce oxygen and glucose. What is the calculation of all final masses when 10.0g CO2 and 10.0g of H2O react

Answer 1

10.0 g CO2 x 1 mole CO2/44.01 g CO2 x 1 glucose/6 CO2 = .0379 mole glucose

10.0 g H2O x 1 mole H2O/18.02 g H2O x 1 glucose/6 H2O = .0925 mole glucose

10.0 g CO2 is the limiting reactant. It will be used up entirely.

10.0 g CO2 x 1 mole CO2/44.01 g CO2 x 1 glucose/6 CO2 = .0379 mole glucose

.0379 mole glucose x 180.16 g glucose/1 mol glucose = 6.83 g glucose

10.0 g CO2 x 1 mole CO2/44.01 g CO2 x 6 O2/6 CO2 = .227 mol O2

.227 mol O2 x 32.00 g O2/1 mol O2 = 7.27 g O2

10.0 g CO2 x 1 mole CO2/44.01 g CO2 x 6 H2O/6 CO2 = .227 mol H2O used

.227 mol H2O x 18.02 g H2O/1 mol H2O = 4.09 g H2O used

10.0 g H2O - 4.09 g H2O = 5.91 g H2O remaining