d = rt

distance = rate of speed times time

c= car speed = 2b-30

2c = 2b+20

c = b + 10

2b-30 = 2b +10

b = 40 mph

c=2(40)-30 = 50 mph

Kim L.

asked • 11/08/18A car in the bus sit out at 2 PM from the same point headed in the same direction the average speed of the car is 30 mph slower than twice the speed of the bus in 2 hours the car is 20 miles ahead of the bus find the rate of the car

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d = rt

distance = rate of speed times time

c= car speed = 2b-30

2c = 2b+20

c = b + 10

2b-30 = 2b +10

b = 40 mph

c=2(40)-30 = 50 mph

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