Work done is the change in kinetic energy.
m = mass of car = 2500 kg, let v2 = final velocity & v1 = initial velocity.
Work = mv2^2/2 - mv1^2/2 = (2500/2)(30^2 - 0) = 1,125,000 N-m
Elisa F.
asked • 11/03/18A 2500 kg car is moving with a speed of 30 m/s. How much work is required to stop the car?
A 2500 kg car is moving with a speed of 30 m/s. How much work is required to stop the car?
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