Physics Plug and Chug

Question

Q=cmΔT

Use the formula to find how many joules it takes to raise the temperature of 0.28 kg of water from 20∘C to 34 ∘C. For the specific heat capacity c, use 4190 J/kg⋅∘C.

Answer 1

As you state, just "plug and chug".

Q = ?

c =4190 J/kgºC

m = 0.28 kg

∆T = 34º - 20º = 14º

Q = (4190 J/kgºC)(0.28 kg)(14º) = 16,425 J = 16,000 J (to 2 significant figures)

Answer 2

The variables in the formula here are

c = specific heat capacity = 4190 J/kg*C

m = 0.28 kg

dT = 34 - 20 = 14

for this set of values that becomes

Q = (4190 J/kg*C) x 0.28 kg x 14 C = 16424.8 J

meaning that it takes 16,424.8 J to meet these criteria