CH3COF + H2O Yields CH3COOH + HF, 28grams of H2O produces a 79.59% yield of HF. How many grams are produced?

Answer 1

CH₃COF + H₂O ==> CH₃COOH + HF .. balanced equation

28 g H₂O x 1 mol/18 g = 1.56 moles H₂O

100 % yield of HF = 1.56 moles x 20.01 g/mole = 31.13 g

If percent yield of H₂O is 79.59%, it is expected that % yield of HF is also 79.59%.

Grams HF produced = 0.7959 x 31.13 g = 24.77 g