Since 2 and 4 are roots, the equation must be a multiple of x2 - 6x + 8 and 5 will serve the purpose:
5x2 - 30x + 40. At x = 3, the quadratic has value -5. The easiest way to compute the multiplier is to substitute A(9 - 18 + 8) = -5 => A = 5.
Khadijah F.
asked 10/25/18What is the quadratic equation of a graph with x intercepts of 2 and 4, and a vertex of 3,-5
Since 2 and 4 are roots, the equation must be a multiple of x2 - 6x + 8 and 5 will serve the purpose:
5x2 - 30x + 40. At x = 3, the quadratic has value -5. The easiest way to compute the multiplier is to substitute A(9 - 18 + 8) = -5 => A = 5.
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