J.R. S. answered 10/25/18
Tutor
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Ph.D. in Biochemistry--University Professor--Chemistry Tutor
1080 kJ/mole * x mole = 263.60 kJ
x = 0.244 moles
mass needed = 0.244 moles x 26.89 g/mole = 6.56 g
Zack C.
Thank you so much that really helps10/25/18