The equilibrium concentrations of A and B for the reaction below are 0.0725 M and 0.0741 M

Question

The equilibrium concentrations of A and B for the reaction below are 0.0725 M and 0.0741 M, respectively. If the equilibrium constant is Kc=17.4223, what is the equilibrium concentration of C?

A(aq)+3B(aq)⇌3C(aq)

Answer 1

Hello Aisha

Kc = [products] / [reactants]

Kc = [C]³ / [A] [B]³

Rearrange and solve for [C]

[C]³ = Kc [A] [B]³

[C]³ = 17.4223 x 0.0725 x (0.0741)³

Complete the above calculation, and then take the cube root of the resultant # to get the equilibrium concentration of C.