
Thien D. answered 07/12/19
Duke MS Engineering Grad For Math Tutoring
I don't think there is a solution.
For instance, there are only a few ways to add two numbers to get a 6 in the ones place when you use the set of numbers given.
These numbers are: (1) 0 + 6, and (2) 3 + 3.
(1) Let's try 0 + 6
Assuming we try 0 + 6, the digits left are: 4 2 3 3 5 9. We now need to add to get a 7 in the tens place.
The remaining numbers that do this are: 5 + 2, and 3 + 4.
Let's try 5+2; the digits left are: 4 3 3 9. We now need to add to get 3 in the hundreds place.
The remaining numbers that do this are: 9 + 4. This leaves us with 3 + 3. The combination of 3950 + 3426 fails, clearly, as the sum is 7376.
Let's back track to the hundreds place and try 3+4; the digits left are: 2 3 5 9. We now need to add to get 3 in the hundreds place. None of these combinations work.
(2) Let's try 3 + 3
Let's back track to the ones place then, 3 + 3. This leaves us with digits of 4 2 0 6 5 9. We now need to add to get a 7 in the tens place. The remaining numbers that do this are: 2 + 5; the digits left are: 4 0 6 9. We now need to add to get a 3 in the hundreds place. The remaining numbers that do this are 9 + 4; the digits left are 0 + 6. The combination of 6453 + 0923 = 7376.
Therefore, all possible combinations fail.