A 32.7 gram piece of metal is held at 20.0°C. What is the final temperature of the metal after 590 joules of heat are added, if the specific heat of the metal is 0.128 J/(g·°C)?

Answer 1

This question is worded poorly. If the temperature is "held" at 20.0 deg C, then it is not changing. I assume you meant to say the INITIAL temperature is 20.0 deg C, and you want the final temperature. Work with the relation

Q = mc(T2 - T1)

T2 = Q/(mc) + T1

Q = 590 J

m = 32.7 g

c = 0.128 J/(g deg C)

T1 = 20.0 deg C

Plug in the numbers and get T2 in deg C.