Making a Solution

Question

Make 50.0ml of a solution that is both 0.15 M in malonic acid, CH2(CO2H)2 and 0.020 M MnSO4.

Tip: Simply Calculate how grams of malonic acid to make 50.0 ml of 0.15 M malonic acid and how many grams of MnSO4 *H2O needed to make 50.0 ml of 0.020 M manganese (II) sulfate solution.

Answer 1

Hello Brook

Use the volume and molarity of the solutions to determine the # of moles. Then use the molar mass to convert moles to grams.

mol Malonic acid (MA) = 0.15 mol/L x 50.0 mL x (1 L / 1000 mL) = 0.00750 mol MA

g MA = 0.00750 mol x (104 g MA / 1 mol MA) = 0.780 g MA

mol MnSO4 * H2O = 0.020 mol/L x 50.0 mL x (1 L / 1000 mL) = 0.00100 mol MnSO4 * H2O

g MnSO4 * H2O = 0.00100 mol x (151 g MA / 1 mol MA) = 0.151 g MnSO4 * H2O