If f(1)=2f(1)=2 and f(n)=f(n-1)+3f(n)=f(n−1)+3 then find the value of f(5)f(5).

Question

i need help on this for my dealtamath homework

Answer 1

f(n) = f(n-1) + 3

f(1) =2

f(1) = 2 = f(1-1) + 3 = f(0) + 3

f(0) = 2-3 = -1

f(0) =-1

f(1) = 2

f(2) = f(2-1)+3 = f(1)+3 =2+3 =5

f(3) = f(3-1)+3 = f(2)+3 = 5+3 =8

f(4) = 8+3 =11

f(5) = 11+3 = 14

f(5)f(5) = 14(14) = 196