Find three consecutive integers whose sum is 48.

Question

use N to represent an integer

 

n=1st integer

n+1= 2nd integer

n+2=3rd integer

Answer 1

so we have:

n + n+1 + n+2 = 48.

simplified, it looks like:

3n + 3 = 48

Subtract 3 from both sides, and we have:

3n = 45

Divide both sides by three to isolate n and we have:

n = 15

so our numbers should be 15, 16, and 17.

Checking out answer, we get that:

15 + 16 + 17 = 48