Inactive Tutor answered 10/09/14
Tutor
New to Wyzant
Rita,
Is this one problem or two? You show two different polynomials which will result in two different solutions. I'll do both since it may help you.
(1) Factor ac + xc = aw2 + xw2
ac - aw2 + xc - xw2 = 0
a(c - w2) + x(c - w2) = 0
(a + x)(c - w2) = 0
(a + x)(c0.5 + w)(c0.5 - w) = 0 , where c0.5 is just a way of writing the square root of c
(2) Factor ac + xc + aw2 = xw2
ac + aw2 + xc - xw2 = 0
a (c + w2) + x(c - w2) = 0
a(c + w2) + x(c0.5 + w)(c0.5 - w) = 0 since (c + w2) can't be factored using real numbers
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