Circle Equation

Question

Find an equation of the circle with center at (4,-6) that is tangent to the y-axis in the form of (x-A)^2+(y-B)^2=C where A, B, C are constant.

 

What is A, B & C?

Answer 1

The equation of circle with center (4,-6). is

 

(x-4)^2+(y+6)^2=r^2

 

Where  r is the radius

 

Since the circle is tangential to y axis

 

So r=4

 

A= 4

B=-6

C=16