A is the event exactly one 6
B is the event at least one 6
P(A) = 6*(1/6)(5/6)11
P(B) = 1 - (5/6)12
P(A|B) = P(A ∩ B)/P(B) but P(A ∩ B) = P(A); therefore P(A|B) = (5/6)11 / [1 - (5/6)12], approximately .15
Paul M.
tutor
There are 6 ways of getting exactly one 6 (on the 1st roll, the 2nd...etc); alternatively this is the 2nd term in the binomial density function.
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10/06/19
Haixing L.
thank u so much, i get it!
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10/06/19
Haixing L.
but i just confused that why the coefficient is not 12c1 cause it rolled 12 times
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10/06/19
Paul M.
tutor
Sorry...you are correct! My error.
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10/06/19
Haixing L.
why p(a)=6*(1/6)(5/6)11 but not (1/6)(5/6)^11? thank u!10/06/19