Rahman W.

asked • 10/05/18

very confusing chem question

he following reaction illustrates the decomposition of hydrogen peroxide (H2O2) to form water and oxygen gas:

2 H2O2 (l) → 2 H2O (l) + O2 (g)

When this reaction is carried out, 0.50 L of O2 gas is collected over water at a total pressure of 1.05 atm. The temperature is 23°C. The vapour pressure of water at this temperature is 0.0278 atm.

What was the mass (in g) of the hydrogen peroxide that decomposed?

1 Expert Answer

By:

J.R. S. answered • 10/06/18

Ph.D. University Professor with 10+ years Tutoring Experience

Julie S.

tutor
Good explanation... but the question asked for the grams of H2O2 that decomposed.  So need to go from moles of O2 to moles of H2O2 and then mass of H2O2.  
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10/06/18

J.R. S.

tutor
Yep. I misread the question. 
0.02103 moles O2 x 2 moles H2O2/mole O2 x 34 g H2O2/mole = g H2O2. 
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10/06/18

Has H.

can you clarify the ending?
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10/04/19

J.R. S.

tutor
What ending? Converting moles O2 to grams H2O2? Or some other ending?
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10/04/19

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