At 600 m/s in 1/3 sec the bullet traveled 200 m. (Distance = rate * time).
The distance the bullet fell in 1/3 sec is given by s = 4.9 * (1/3)2 = .53333 m where 4.9 is 1/2 of the acceleration due to gravity.
Jake N.
asked 10/05/18
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