Ishwar S. answered 10/04/18
Tutor
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(7)
University Professor - General and Organic Chemistry
Hello Mykayla
For each compound, divide the molar mass of H2O by the molar mass of the compound and multiply the result by 100% to get the %-composition of water in the hydrated compound.
a) LiNO3 • 3H2O
Total mass of H2O in hydrate = (18.02 g / mol) x 3 mol = 54.06 g H2O
%-H2O = (54.06 / 122.95) x 100% = 43.97%
b) Ca(NO3)2 • 4H2O
Total mass of H2O in hydrate = (18.02 g / mol) x 4 mol = 72.08 g H2O
%-H2O = (72.08 / 236.10) x 100% = 30.53% (**Your answer**)
Total mass of H2O in hydrate = (18.02 g / mol) x 4 mol = 72.08 g H2O
%-H2O = (72.08 / 236.10) x 100% = 30.53% (**Your answer**)
c) Sr(NO3)2 • 4H2O
Total mass of H2O in hydrate = (18.02 g / mol) x 4 mol = 72.08 g H2O
%-H2O = (72.08 / 283.64) x 100% = 25.41%
Total mass of H2O in hydrate = (18.02 g / mol) x 4 mol = 72.08 g H2O
%-H2O = (72.08 / 283.64) x 100% = 25.41%