Lauren H. answered 10/03/18
Tutor
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7 years experience teaching High School Chemistry and Honors Chemistry
A 10.0 cm long cylindrical glass tube, sealed at one end, is filled with ethanol. The mass of ethanol needed to fill the tube is found to be 12.30 g . The dens.
Vol of cyl = (πr^2)h
h = 10.0 cm
12.30 g etoh x (1 kg/1000g) x (1m^3/789 kg) = 1.56 m^3
1.56 m^3 x (100 cm/m)^3 = 15.6 cm^3
This is the vol of the etoh and therefore the vol of the interior cylinder
15.6 cm^3 = (πr^2)h = (πr^2)10.0 cm
1.56 cm^2 = πr^2
.496 cm^2 = r^2
.705 cm = r
d = 2r = 1.41 cm