
Naomi S. answered 10/03/18
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cost of renting 1 chair = x
cost of renting 1 tables = y
6x+2y = 30 ---------- eq 1
3x+5y =48 -----------eq 2
solve these 2 equation simultaneously
30x +10y = 150 ---------multiplying eq 1 with 5
6x +10y = 96---------multiplying eq 2 with 2
subtracting these equations
24x = 54
x= 2.25
substituting x=2.25 in equation 1
6(2.25)+2y=30
13.5 +2y =30
2y = 16.5
y = 8.25
cost of renting 1 chair = x =$2.25
cost of renting 1 tables = y =$8.25
cost of renting 1 tables = y =$8.25