Vertical and horizontal asymptotes of 4/(x^2+1)

Question

Vertical and horizontal asymptotes of 4/(x^2+1)

Answer 1

y = 4/(x²+1)

 

   x²+1 ≠0 if x is real.  So, there are no vertical asymptotes.  

 

   As x→±∞, 4x²+1→∞, so 4/(x²+1)→0    Horizontal asymptote is y = 0 (the x-axis).