Arthur D. answered 10/05/14
Tutor
4.9
(274)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
If you can make sets of 2 beads, sets of 4 beads, and sets of 5 beads, and not have any left over, you want the least common multiple of 2,4, and5 which is 20. You can write multiples of 20 until you get the correct answer.
20/9=2 R2
40/9=4 R4
60/9=6 R6
80/9=8 R8
100/9=11 R1
120/9=13 R3
140/9=15 R5
160/9=17 R7 answer
160 is the smallest multiple of 20 such that when you divide it by 9 you have 7 as a remainder
160 is the fewest number of beads whereby you can make sets of 2, 4, and 5 but when you make sets of 9 you get 17 sets and 7 beads remaining
a simpler approach is to multiply 20 by 9 to get 180, but 180 is divisible by 9 with no remainder
now work backwards and use the multiple 160 and as you have seen 160/9=17 R7
you also should see a pattern of remainders with the first solution:
remainder 2, then 4, then 6, 8, 1, 3, 5, and finally 7