How do I condense log - log + log

Question

I understand the rules of logarithms but am confused as to what order to go about condensing this 

Answer 1

First, you need to have arguments for the logs.  Assuming they are different,

 

log(x) - log(y) + log(z) = log(x/y) + log(z) = log(xz/y)

 

You can also do it in the order

 

log(x) + [-log(y) + log(z)] = log(x) + log(z/y) = log(xz/y)

 

Just work with two at a time.