Chemistry homework help

Question

Write a balanced metathesis equation for the reaction which takes place when the two solutions described below are combined and then determine the amount of solid product produced.

250.0 ml of 0.200 M solution of FeCl3 is combined with 400.0 ml of 0.350 M KOH solution. How many grams of solid iron (III) hydroxide will be produced by the reaction. Assume 100% yield.

Answer 1

Hello Jana,

 

The balanced equation:

 

FeCl₃(aq)        +       3 KOH(aq)  -----------------  Fe(OH)₃(s)        +      3 KCl(aq)

 

mole ratio:        1 mol                       3 mol                                  1 mol                        3 mol

 

 

 

250.0 ml of 0.200 M solution of FeCl3   =  0.250 L x 0.200 mol/L  =  0.05 mol FeCl3

 

400.0 ml of 0.350 M KOH                   =   0.400 L  x 0.350 mol/L  =  0.14 mol KOH

 

 

Consider 0.05 mol FeCl3:

 

mol of Fe(OH)3 formed =  (1 mol Fe(OH)3/1 mol FeCl3) x 0.05 mol FeCl3 = 0.05 mol Fe(OH)3

 

 

Consider 0.14 mol KOH:

 

mol of Fe(OH3) formed =  (1 mol Fe(OH)3/3 mol KOH) x 0.14 mol KOH   = 0.047 mol Fe(OH)3

 

 

Thus, 0.047 mol Fe(OH)3 will be formed . Using the molar mass of Fe(OH)3 = 106. 86 g/mol

 

0.047 mol Fe(OH)3 x 106.86 g/mol = 5.0 g Fe(OH)3 will be produced.

 

 

Comment: This problem is similar to the previous one. Thus, refer to the previous problem for the explanation.