The sum of 5 consecutive integers is 505

Question

How would i figure this out 

Answer 1

505/5=101

101-1=100

100-1=99

101+1=102

101+2=103

99, 100, 101, 102, 103

if you are in algebra and need work use Carol H.'s solution

Answer 2

Let the five consecutive integers be;

x

x+1

x+2

Add them together to get 505:

x + x + 1 + x + 2 = 505

3x = 502

Solve for x,

then solve for x + 1,

then solve for x + 2.

Answer 3

let x = the smallest integer

let x + 1 = the second integer

let x + 2  = the third integer

let x + 3 = the fourth integer

let x + 4 = the largest integer

x + x + 1 + x + 2 + x + 3 + x + 4 = 505

5x + 10 = 505

5x = 495

x = 99

x + 1 = 100

x + 2 = 101

x + 3 = 102

x + 4 = 103