Patrick B. answered 03/15/20
Math and computer tutor/teacher
it takes the 2nd engine x hours
it takes the 1st engine x+6 hours.
the work rate of the first engine is 1/(x+6) and the work rate of the second engine is 1/x
the combined work rate is 1/(x+6) + 1/x = 1/4
It takes 4 hours for both of them, so the combined work rate is 1/4
1/(x+6) + 1/x = 1/4
Multiplies by 4x(x+6)
4x + 4(x+6) = x(x+6)
4x + 4x + 24 = x^2 + 6x
8x + 24 = x^2 + 6x
0 = x^2 - 2x - 24
0 = ( x - 6 )( x + 4 )
x-6 = 0 or x+4 = 0
x+4=0 results in negative measures
x-6 = 0 ---> x = 6
it takes the 2nd engine 6 hours ---> work rate is 1/6
it takes the 1st engine 12 hours ---> work rate is 1/12
1/6 + 1/12 = 2/12 + 1/12 = 3/12 = 1/4 is the combined work rate.
It takes 4 hours for both of them.