
Nestor R. answered 08/13/19
Statistician with a very good grounding in Algebra
Area = LxW = 224
L = 2xW + 12
So, using 2W+12 in place of L, the area is
(2W + 12) x W = 2W2 +12W = 224
Subtract 224 from both sides to get
2W2 +12W - 224 = 0
Divide all terms by 2
W2 + 6W - 112 = 0
Use quadratic formula to find 2 solutions for W. a=1, b=6, c=-112
[-b +/- sqrt(b2 - 4ac)] / 2a
[-6 +/- sqrt(36 - (-448))] / 2
(-6 +/- 22) / 2
Possible solutions are (-6 + 22) / 2 = 16/2 = 8 AND (-6 - 22) / 2 = -28 / 2 = -14
The only solution that works is W = 8
Area = 224 = L x W ==> 224 = L x 8 ==> 224/8 = 28 = L
L = 2xW + 12 ==> 2x8 + 12 ==> 16+12 ==> 28 meeting conditions of the problem.