y = g(x) = 3x - 17
h(g(x)) = (3x - 17)2 + 17
at x = 2, (6 - 17)2 + 17 = 121 + 17
Paul M.
tutor
I will show you in older notation which is sometimes easier to understand. Let h(y) = y^2 + 17. Now let y = 3x - 17. Now substitute the expression for y [which is g(x)] into h(y)...i.e. (3x - 17)^2 + 17. Now you have h(g(x)). Substitute 2 for x to get h(g(2)), i.e. (6 - 17)^2 + 17 as before. It would have been a little easier to see if the problem had not used the same constant (17) in 2 different places. I hope that helps.
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09/26/18
Annie X.
09/26/18