Given: <A is complementary, <B and <C is Complementary to D, and <B is congruent to <C Prove: m<A=m<D

Question

My quesiton involves having to be given with statements and reasons.

Answer 1

 

A+B = 90 <--- A and B are complementary is given

 

B+D = 90 = C+D <--- B and C are complementary to D is given; then transitive property

             

B = C <---- subtracts D from both sides

 

A+C = 90 <--- substitutes B=C in first equation

 

C + D = 90 <--- C and D are complementary is given

 

A+C = C= D <--- transitive

 

A=D <--- subtracts C from both sidfes

 

their measures are the same <--- property of equal angles