I need a rectangle with a perimeter of 22 inches and an area less than 24 square inches.

Question

I need a rectangle with a perimeter of 22 inches and an area less than 24 square inches.

Answer 1

Hi, Jordan. You need the perimeter of 22 and area less than 24.

 

Perimeter = 2L + 2 W = 22

 

2(L + W) = 22

L + W = 11

 

You need 2 numbers that add to 11 and multiply less than 24.

 6 x 5 = 30....too big

4 x 7 = 29 ....too big

3 x 8 = 24....still too big

2 x 9 = 18  That'll work.

 

So, if the rectangle is 2 inches wide and 9 inches long,

the Perimeter is 2(11) = 22

The Area = 2 x 9 = 18 sq. in.