Chemistry problem

Question

A metal ball has a density of 8.13 g/cc and a mass of 332 g. If it is placed into a graduate that already contains 28.7 mL of water, what will be the final reading on that graduate? 

Answer 1

Hello Nick

 

Use the mass and density of the metal ball to calculate the volume it occupies.

 

d = m/V

 

V = m/d

 

   = 332 / 8.13 = 40.8 cc

 

1 cc = 1 mL

 

40.8 cc = 40.8 mL

 

Final volume in cylinder = volume of water + volume of metal ball.

 

= 28.7 + 40.8 = 69.5 mL

Answer 2

A metal ball has a density of 8.13 g/cc and a mass of 332 g

d = m/v

8.13 g/cc  =  332g/v

v = 40.8 cc

28.7 mL x 1 cc/mL = 28.7 cc water+ 40.8cc metal ball = 69.5 cc