Mark B. answered • 09/15/18
Tutor
New to Wyzant
PhD Candidate in Psychology: Experienced Math, Statistics, Tutor
Good Afternoon, Joshua,
Let's assign x to the first integer, and x + 1 be the second consecutive integer, okay? Therefore, according to the problem:
x + 5(x + 1) = 65
Notice Joshua, x has been "added to five times the larger" giving the result of 65. Now let's solve.
x + 5x + 5 = 65
6x + 5 = 65 <---Subtract 5 from both sides of equation
6x = 60
x = 10 <----This is the smaller integer.
x + 1 = 11 <----This is the second integer.
Let's check our work Joshua by plugging our numbers into our original equation, okay?
x + 5(x +1) = 65
10 + 5(11) = 65
10 + 55 = 65
65 = 65 <----The equation checks out and is proofed.
I hope this assists you and that you have a great weekend. Please provide any feedback or further questions about this solution in the comment section below. If you need further assistance, please feel free to ask any tutor.
Let's assign x to the first integer, and x + 1 be the second consecutive integer, okay? Therefore, according to the problem:
x + 5(x + 1) = 65
Notice Joshua, x has been "added to five times the larger" giving the result of 65. Now let's solve.
x + 5x + 5 = 65
6x + 5 = 65 <---Subtract 5 from both sides of equation
6x = 60
x = 10 <----This is the smaller integer.
x + 1 = 11 <----This is the second integer.
Let's check our work Joshua by plugging our numbers into our original equation, okay?
x + 5(x +1) = 65
10 + 5(11) = 65
10 + 55 = 65
65 = 65 <----The equation checks out and is proofed.
I hope this assists you and that you have a great weekend. Please provide any feedback or further questions about this solution in the comment section below. If you need further assistance, please feel free to ask any tutor.
