Calculate the mass of sodium acetate (CH3COO0Na) required to make 500 ml of 0.375 molar aqeous solution . Molar mass of sodium acetate is 82.0245 g mol

Question

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Answer 1

Hi Aditya,

 

The molarity of solution is calculated using:

 

                  Molarity  = mole of solute/ Liter of solution

 

Thus, you can rearrange the equation and calculate # of mole of solute and then find the corresponding mass using molar mass.

 

mol of sodium acetate = Molarity x Liter of solution

                                 = (0.375 mol/L)  x (0.5 L)

                                 = 0. 1875 mol

 

The mass of odium acetate = 0.1875 mol x 82.02 g/mol 

                                        =  15.37 g