Let the numbers be N and N+1

5(N) - 3(N+1) = 51

2N - 3 = 51

2N = 54

N =

**27**N + 1 =

**28**Shiquavien A.

asked • 09/10/18There are three consecutive integers half the sum of the first and third number is 28 what are the integers

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Let the numbers be N and N+1

5(N) - 3(N+1) = 51

2N - 3 = 51

2N = 54

N = **27**

N + 1 = **28**

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