David M. answered 09/03/18
Tutor
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Dave "The Math Whiz"
This is a problem with two unknowns, # of upper deck tickets and # of lower deck tickets, so you will need two equations to solve for them.
Let's let x = # of upper deck tickets
y = # of lower deck tickets
Eq. I: We know that you bought 15 tickets, so
x+y=15
Eq. II: We know that the total cost was $570, so
30x+45y=570
You can use the substitution method or elimination method to solve for either x or y. Let's use the substitution method and solve for x. From Eq. I:
x+y=15--->y=15-x
Use this "value" for y in Eq. II to solve for x:
30x+45y=570
30x+45(15-x)=570
30x+675-45x=570
-15x+675=570
-15x=570-675
-15x=-105
x=7
Now, putting this value for x back into Eq. I we can solve for y:
x+y=15
7+y=15
y=15-7
y=8
We shall now check that both equations are met with these values:
Eq. I: x+y=15 Eq. II: 30x+45y=570
7+8=15 30(7)+45(8)=570
15=15 210+360=570
Check 570=570
Check
Therefore, the answer is that you bought 7 upper deck and 8 lower deck tickets.