Chemistry - Solubility Product

Question

The solubility product of calcium sulfate is approximately as follows under the temperature conditions in question:

[Ca2+ ] x [SO42- ] = 2.5 x 10–5(mole/liter)2

You also have been given the following data related to the concentrations of calcium and sulfate ions:

[Ca2+ ] = 1.5 mmole/L

[SO42- ] = 3.8 mmole/L


What is the concentration of sulfate ions in moles per liter (show units!)?

 

What is the product of the calcium and sulfate ion concentrations?

Answer 1

Josh, I'm not sure I understand this problem, but...

 

[SO42- ] = 3.8 mmole/L 

 

3.8 mmole/L  x 1mole/10^3mmole = 3.8 x 10^-3 mole/L

 

What is the product of the calcium and sulfate ion concentrations?

 

 

(3.8 x 10^-3)  x (1.5 x 10^-3) = 5.7 x 10^-6

 

This is < the solubility product of 2.5 x 10–5(mole/liter)2

 

Not sure if this helps you....