Chemistry HW

Question

Suppose that you wish to make a very dilute solution of lemonade. If you take a lemonade mixture that is half of the concentration recommended on the package (call it 0.5x) and mix 10 mLs of it with 30 mLs of water, what is the final concentration (in terms of x)?
Recall that C1 x V1 = C2 x V2
where C = concentration and V = volume.

Answer 1

Hello Nelson

 

You are starting with half of the recommended concentration of the lemonade mixture. This equates to a concentration of 50%.

 

You measure 10 mL of this 50% solution and add 30 mL of water. The total (final) volume of the solution = 10 + 30 = 40 mL.

 

C₁V₁ = C₂V₂

 

C₂ = C₁V₁ / V₂

 

     = (50% x 10 mL) / 40 mL

 

     = 12.5%