SURENDRA K. answered • 09/23/14
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For x= 0 it is 0/0 form
So, we can apply L' Hopital's rule.
5sin(5x)/(-6sin(6x))
=(-5/6)*(sin(5x)/5x)*(6x/sin(6x))*(5x/6x)
On taking limits now
= (-5/6)*(5/6)
=-25/36
We are using the standard result here----
limit. sin(x)/x. as x tends to 0
=1
So, limit sin(5x)/5x. as x tends to 0
=1
And,
Limit sin(6x)/6x. as x tends to 0
=1
SURENDRA K.
If you want to learn limits fully well,
You have to learn L'Hopital's rule.
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09/24/14
Sarah J.
look, my teacher hasnt taught this to us yet and this was a question on the test. i want to learn how to do this without the use of l'hopitals rule or derivatives sop could you please just tell me how?
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09/24/14
Sarah J.
09/23/14