Ze L. answered 09/25/14
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AP/College Physics, Calculus, Chem, Programming Specialist
30+15+19 = 64 is the total number of students in the 3 language classes. There are 50 total students so there must be 14 overlaps. 6 english/german students covers 6 overlaps. Similarly, 7 and 5 cover 12 overlaps. 6+12=18 given overlaps, showing 4 excess. So there must be 4 students taking all 3 subjects.
To double check, we state how many students are doing exactly 2 subjects. 4 students doing all three implies 2 are doing E/G, 3 doing F/E, and 1 doing F/G. The double subject students gives us 2+3+1 = 6 overlaps. The triple subject students gives us 2 overlaps each so that adds up to 6+4*2=14.