A tennis player hits a ball 3 feet above the ground with a velocity of 45 ft/sec. What is the maximum height the ball will reach (Round to 3 decimal places)

Question

The two formulas that you need are:

h = -16t2 + s

h = -16t2 +vt + s

Answer 1

Initial height s=3

 

initial velocity is 45

 

h(t) = -16t^2 + 45t + 3

 

The max occurs at the AVERAGEs of the zeros of this quadratic function.

So you will have to run 16t^2 - 45t - 3 = 0 through the quadratic formula: A=16, B=-45, t = -3.

The two solutions shall be x=-0.065 and x=2.878

The average is 1.4065

The max height is 34.641 feet = 34 feet 7 and 3/4 inches