First let's calculate the volume of the pipe line at 4000*pi cubic feet. We have to convert this to gallons.
4000*pi cubic feet*12^3 inches^3*2.54^3 cm^3* 1ml *1 liter *.264 gallons
-------------- ---------------- ----------- --------- --------------- = 93894.13 gallons
1ft^3 inches^3 cm^3 1000ml liter
At 10000 gallons per minute that's 9.3894 minutes to fill the pipeline.
Concentration decays at V0*e^-tk were V0=3mg/L. Here tk=9.3894*.09=.845. e^-.845=.4296.
.4296*3=1.29mg/L.
Hope that helps,
Deanna