Arthur D. answered 09/17/14
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distance=rate*time
d=rt
d=50t
d=175(t-5)
50t=175(t-5)
50t=175t-875
50t-175t=-875
-125t=-875
125t=875
t=875/125
t=7 hours
d=50*7
d=350 miles from the station