solve 3(x+1) +2(3x+3) = 45

Question

 solve 3(x+1) +2(3x+3) = 45

Answer 1

Attack each expression individually, then isolate and solve for x:

 

Step 1

Multiply the coefficient, "3", by each term in the parentheses next to it

 

3(x+1) = (3*x + 3*1) = 3x + 3

 

 

Step 2

Multiply the coefficient, "2", by each term in the parentheses next to it

 

2(3x+3) = (2*3x +2*3) = 6x + 12

 

 

Step 3

Add both the resulting binomials

 

3x + 3 + 6x + 12 = 9x + 15

 

 

Step 4

Set this equal to what's on the other side of the "="

 

9x + 15 = 45

 

 

Step 5

To isolate "x", subtract 15 from both sides of the equation

 

9x + 15 - 15 = 45 -15

 

9x = 30

 

 

Step 6

Divide both sides of the equation by the coefficient of x, which, in this case, is 9.

 

x = 30/9 = 3 3/9 = 3 1/3 = 3.33333...