The sum of three consecutive even integers is 198. Find the integers.

Question

The sum of three consecutive even integers is 198. Find the integers. The three consecutive even integers are

Answer 1

Let the first even integer be x

Second even integer: x+2

Third even integer: x+4 

 

Their sum must be 198. Remember that "is" means equals. So, we get x+(x+2)+(x+4)=198

 

3x+6=198, Therefore x=64

 

That means the integers are as follows; 64,66,68.

Answer 2

consecutive even integers are separated by 2.... such as 2, 4 and 4, 6

Let the consecutive integers be:  x, x+2, x+4

 

x + (x+2) + (x+4) = 198

3x + 6 = 198

3x = 192

x = 64

x+2 = 66

x+4 = 68