How many grams of CH3NH3Cl were used up?

Question

0.63 g of methyl amine was produced by the reaction: CH3NH3Cl +NaOH ---> CH3NH2 + NaCl +H2O . (1)How many grams of CH3NH3Cl were used up?

Answer 1

 

Look at the coefficient, and then convert the mol to gram by using the molar mass.

 

 

               CH3NH3Cl    +      NaOH --->   CH3NH2      +     NaCl +     H2O

 

mol:         1mol                                       1mol

 

 

gram:        67.5 g                                     31 g

 

 

Thus, according to the reaction 67.5 g CH3NH3Cl is required to produce 31 g CH3NH2. Based on this ratio,

 

 

                       (67.5 g CH3NH3Cl/31 gCH3NH2) x 0.63 g CH3NH2  =  1.37 g CH3NH3Cl were used up.