What is the osmotic pressure of a solution made up of 2.00g sucrose in 100mL of solution at 30C?

Question

I need this.

Answer 1

The first step is convert the grams of sucrose into moles.

 

Moles sucrose= 2.00 g/ 342.3 g/mol= 5.84 x 10^-3 moles

 

Molarity of sucrose solution= 5.84 x 10^-3/ 0.1 L= 0.0584 M

 

The next step is to use the equation for osmotic pressure (Π):

 

Π= MRT 

where

M= molarity of solution= 0.0584 mol/L

R= ideal gas constant= 0.0802 L atm/ mol K

T= temperature (in Kelvin)= 30°C + 273.15 K= 303.15 K

 

Π= (0.0584 mol/L)(0.0802 L atm/ mol K)(303.15 K)

Π= 1.42 atm

 

The final answer is that osmotic pressure of that sucrose solution at 30°C is 1.42 atm.