Ishwar S. answered 06/02/18
Tutor
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(7)
University Professor - General and Organic Chemistry
Hello Hussein
As per the solubility rules, zinc sulfide (ZnS) is an insoluble ionic compound. When sulfides react with acids, they form hydrogen sulfide (H2S) gas as one of the products. From this information, you can write the molecular equation as:
ZnS (s) + 2 HI (aq) ---> ZnI2 (aq) + H2S (g)
Hydroiodic acid is a strong acid, and will ionize to form H+ and I- ions in an aqueous solution. Hence, the ionic equation is:
ZnS (s) + 2 H+ (aq) + 2 I- (aq) ---> Zn2+ (aq) + 2 I- (aq) + H2S (g)
From the ionic equation, you can see that the iodide ion (I-) is a spectator ion, and you can therefore, cancel it from the reactant and product side of the equation giving the net ionic equation as follows:
ZnS (s) + 2 H+ (aq) ---> Zn2+ (aq) + H2S (g)