
Tesfaye D. answered 06/02/18
Tutor
New to Wyzant
PhD in Chemistry with Research and Teaching Experiences
The balanced equation
2 SO2(g) + O2(g) --------- SO3(g)
mol: 2 mol 1mol
gram: 2 x 64 g 1 x 32 g (convert the mol to gram using molar mass for SO2 and O2)
The amount of O2 required to completely react with SO2 can be calculated using the ratio from the above equation:
1 x 32 g O2/(2 x 64g SO2)
Thus, for 31.1 g SO2
[1 x 32 g O2/(2 x 64g SO2)] x 31.1 g SO2 = 7. 78 g O2 is required.